Compute dy/dx and d^2y/dx^2 for parametric curves x(t), y(t)
Parametric derivatives allow finding slopes of parametric curves without eliminating the parameter. The first derivative dy/dx gives the tangent slope. The second derivative gives concavity of the parametric curve.
Parametric equations describe curves using a parameter t. The derivative dy/dx gives the slope of the tangent to the parametric curve. The chain rule directly gives dy/dx = (dy/dt)/(dx/dt). The second derivative reveals concavity.
dy/dx = y/x. Differentiate both parametric equations, then divide y by x. Gives slope at any t.
d^2y/dx^2 = (d/dt(y/x))/x. Differentiate the first derivative with respect to t, then divide by x again.
At parameter t0, slope = dy/dx at t0. Tangent line: y-y(t0)=m*(x-x(t0)). Horizontal when y=0, vertical when x=0.
Motion analysis (velocity vector = (x,y)), curve sketching, arc length, surface area of revolution.
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