Compute (1/(b-a))*integral_a^b f(x) dx for linear, quadratic, and sine functions
The average value of a function on an interval is the constant that would give the same area under the curve. By the Mean Value Theorem for Integrals, a continuous function attains its average value at some point in the interval.
The average value of a function generalizes the arithmetic mean to continuous functions. Instead of averaging discrete values, it computes the integral (total area) divided by the interval length. The Mean Value Theorem guarantees the function hits this value somewhere.
f_avg = (1/(b-a)) * int_a^b f(x)dx. Integrate first, then divide by interval length.
There exists c in [a,b] such that f(c) = f_avg. The function must be continuous. Guarantees the average is achieved.
The rectangle with height f_avg has the same area as the area under f(x) from a to b.
Average temperature, average velocity (mean value theorem), average current, average signal power in engineering.
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